(1/27)^4x=81^(3x-9)

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Solution for (1/27)^4x=81^(3x-9) equation: 



(1/27)^4x=81^(3x-9)

We move all terms to the left:

(1/27)^4x-(81^(3x-9))=0



Domain of the equation: 27)^4x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/27)^4x-(81^(3x-9))=0

We multiply all the terms by the denominator


(+1-((81^(3x-9)))*27)^4x=0

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